9514 1404 393
Answer:
b. angle K is acute
Step-by-step explanation:
We're often told not to draw any conclusions from the appearance of a figure in a geometry problem. Here, angle K appears to be somewhat less than 90°, so angle K is acute.
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<em>Additional comment</em>
This choice of answer is confirmed by the fact that the other two (visible) choices say the same thing. If one of them is correct, so is the other one. Hence they must both be incorrect. (An obtuse angle is more than 90°.)
3 times X squared minus 4 times X =
<span>a=<span><span><span>bx</span>+<span>cx</span></span>+<span><span>
[email protected]</span>x</span></span></span><span>a=<span><span><span>bx</span>+<span>cx</span></span>+d</span></span>Solve for: Let's solve for a.<span>a=<span><span><span>bx</span>+<span>cx</span></span>+d</span></span>Answer:<span>a=<span><span><span>bx</span>+<span>cx</span></span>+d</span></span>
Answer:
sqrt5/5
Step-by-step explanation:
Answer:
Problem 20)
Problem 21)
A)
The velocity function is:
The acceleration function is:
B)
Step-by-step explanation:
Problem 20)
We want to differentiate the equation:
We can take the natural log of both sides. This yields:
Since ln(aᵇ) = bln(a):
Take the derivative of both sides with respect to <em>x: </em>
<em /><em />
Implicitly differentiate the left and use the product rule on the right. Therefore:
Simplify:
Simplify and multiply both sides by <em>y: </em>
<em /><em />
Since <em>y</em> = (cos x)ˣ:
Problem 21)
We are given the position function of a particle:
A)
Recall that the velocity function is the derivative of the position function. Hence:
Differentiate:
The acceleration function is the derivative of the velocity function. Hence:
Differentiate:
B)
The position at <em>t</em> = 0 will be:
The velocity at <em>t</em> = 0 will be:
And the acceleration at <em>t</em> = 0 will be: