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Darya [45]
3 years ago
15

Multiply the fractions together. B Divide 45 5 4 by 13 3 1 . C Multiply the numerators together, and multiply the denominators t

ogether. D Divide 13 3 1 by 45 5 4 .
Mathematics
1 answer:
trasher [3.6K]3 years ago
4 0
So we do 5 divide by 4 squeals 10 bye
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Please help me lol
Svetach [21]

Answer:

ATP is made for the instance so you don't run out of energy. Fat stores glycogen which can be broken down into glucose and turned into ATP. I don't know what you're asking specifically thought it's a bit jumbled.

6 0
3 years ago
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Which statement is NOT true of the equation y = 0.5x?
aev [14]

Answer:

it would be C do to the fact that 0.5 x 8=4

3 0
3 years ago
Suppose two radii of a circle determine a 45° angle, and the length of both radii is 64 yards. What is the arc length formed by
Ilia_Sergeevich [38]

The arc length formed by the 2 radio is 15.24 yards

Step-by-step explanation:

Angle between the 2 radio = 45°

Radius = 64 yards

Arc length = (45/360) (2π) (64)

= (1/8) (2π) (64

= 16π

= 16(3.14)

=15.24 yards

The arc length formed by the 2 radio is 15.24 yards

8 0
4 years ago
Denise and Jacqueline are training for a swimming and running race.
bezimeni [28]

Answer:

Jacqueline runs at 6.25 minutes per mile

Step-by-step explanation:

Here we have that the total training time for Jacqueline = 54 minutes

The time for which Jacqueline swims = 30 minutes

Therefore, the time in which Jacqueline runs = 54 min. - 30 min. = 20 minutes

Therefore the equation for Jacqueline's speed = Distance/Time we have

Jacqueline's pace = 3.2 miles/20 minutes = 0.16 miles/minute

Therefore Jacqueline's pace = 0.16 miles/minute

The equation for Jacqueline's pace in miles/minute is presented as follows

Jacqueline's pace in miles/minute = Time of running/Distance

Jacqueline's pace in miles/minute  = 1/0.16 miles/minute = 6.25 minutes/mile.

5 0
3 years ago
Find the mean of the given data set: (12, 2, 6, 3, 3, 19)
Savatey [412]

Answer:

Step-by-step explanation:

hope this helps you

4 0
3 years ago
Read 2 more answers
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