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Vika [28.1K]
3 years ago
7

please help me, I'm stuck on the second one. ​Also for i) i got angle ABD because angles in a semicircle measures 90 degree and

OAX because the angle between the tangent and a radius is 90 degrees

Mathematics
1 answer:
True [87]3 years ago
5 0

Answer:

i)

  • <em>DA is diameter and AX is tangent to circle</em>

<u>Your answer is correct</u>

  • m∠ABD = 90°, m∠DAX = 90°

ii)

<u>Given m∠BAX = 42° and ∠DAB is complementary with BAX ⇒ </u>

  • m∠DAB = 90° - 42° = 48°

<u>DC = BC ⇒ intercepted arcs are same ⇒ </u>

  • ∠CDB = ∠BDC

<u>mDC = mCB ⇒ mDCB = ∠DAB = 48° ⇒ </u>

  • m∠CDB = m∠BDC = 1/2*48 = 24°

iii)

∠CBA

<u>∠CBA is supplementary with ∠ADC as opposite angles of cyclic quadrilateral (∠ADB = ∠BAX = 42°)</u>

  • m∠ADC = m∠ADB  + m∠CDB = 42° + 24° = 68°
  • m∠CBA = 180° - m∠ADC = 180° - 68° = 112°

∠BAE

EA║CB and AB is transversal ⇒ CBA and BAE are supplementary angles:

  • m∠BAE = 180° - 112° = 68°

∠DCE

  • ∠DCE = ∠DCB - ∠BCE
  • m∠DCB = 180° - m∠DAB = 180° - 48° = 132°
  • m∠BCE = 180° - m∠BAE = 180° - 68° = 112°
  • ∠DCE = 132° - 112° = 20°
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