Let $x$ be the amount of the 30% alloy and $y$ the amount of the 60% alloy the metalworker will use. However much is used, the final alloy will have a mass of

$x+y=100$

kilograms. For each kg of the 30% alloy used, 0.3 kg is copper; similary, each kg of the 60% alloy contributes 0.6 kg, so that

$0.3x+0.6y=0.54(x+y)=54$

Now,

$x+y=100\implies y=100-x$

$\implies0.3x+0.6(100-x)=54$

$\implies60-0.3x=54$

$\implies0.3x=6$

$\implies x=20$

$\implies y=100-20=80$

6 0

4 years ago

Describe some possible combinations (at least 2) of 4-seat tables and 6-seat tables that will seat 160 customers. Explain how yo

MrMuchimi

Answer:

You could do 50 2 seat tables and 5 4 seat tables

You could do you could do 40 2 seat tables and 10 4 seat tables

Step-by-step explanation:

brainliest plz

6 0

3 years ago

If their food and beverages cost $25.30 and there is an 8% meals tax, how much is the bill? Enter your answer to the nearest cen

Aneli [31]

Answer:58.60

Step-by-step explanation:

because this was just a wasted of you time very not sorry thx for the pts .

6 0

3 years ago