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2 years ago

Evaluate. (5.2 + 3) × (6.4 - 1.4)

Mathematics

2 answers:

Illusion [34]2 years ago

8 0

Answer: 41

Hope this helps ^W^

zloy xaker [14]2 years ago

6 0

I believe it should be 41

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What is equivalent form of the expression 15x + 24ax

neonofarm [45]

15x + 24ax = 3x(5+8a)

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2 years ago

Please answer asap!!!!

Ivanshal [37]

Answer:

180 - 61 = 119

Step-by-step explanation:

So from A to D it is 180 degrees so just have to subtract 61 from 180 for an answer.

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2 years ago

Need assistance with algebra 2

crimeas [40]

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<u>A. Quadratic, degree 2</u>

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2 years ago

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

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2 years ago

Somebody please help im giving 20 points and a brainliest !

rosijanka [135]

Answer:

Initial is $26000

It's representing decay.

9.1% change each year.

7 0

2 years ago

Evaluate. (5.2 + 3) × (6.4 - 1.4) ​

Evaluate. (5.2 + 3) × (6.4 - 1.4)