Answer:
166 2/13 deg
Step-by-step explanation:
The sum of the measures of the interior angles of a convex polygon of n sides is 180(n - 2).
A hexagon has 6 sides, so n = 6.
sum of measures of angles = 180(n - 2) = 180(6 - 2) = 180(4) = 720
4x + 5x + 6x + 7x + 8x + 9x = 720
39x = 720
x = 720/39
x = 240/13
The largest angle has measure 9x.
9x = 9 * 240/13 = 2160/13
2160/13 = 166 2/13
Answer: 166 2/13 deg
Divide 2 by 5.
you get .4
to make a number a percent, you shift the decimal two placed to the right.
so 2/5=.4=40%
Basically what you need to do is draw 4 congruent rectangles and 2 comgriemt squares (The six sides of a rectangular prism). The sum of the area of these six quadrilaterals should equal 96. This would be my thought process.
Step 1: Sketch a Rectangular Prism
Step 2: Make some educated guesses on some possible side measurements for the quadrilaterals that form the prism.
Step 3: Guess and Check until the amount equals 96.
So we can guess that the sides of the rectangle might equal 2 and 3 units.
This would be 6 for the area. Times 4 for each of the 4 Rectangles. (24) and add the area of the ends of the prism (2*2*2) which is 8 and you will get 32.
Since we are looking for a surface area of 96 and not 32, we can assume that a 3*2*2 prism is not what we need. So we can try again with other values.
Let's try 6*3*3. 6*3*4 for the four rectangles plus 3*3*2 for the ends.
Copy down the given function:
f(x)=3•2^x
Now replace both instances of x with -2:
f(-2) = 3*2^(-2). 1
Recall that 2^(-2) is the same as ------ = 1/4
2^2
Therefore, f(-2) = 3*2^(-2) = 3*(1/4) = 3/4
Remember that exponentiation has to be carried out before multiplication. That's why I did 2^(-2) before multiplying by 3.
1. The remaing area of the yard will be found as follows:
Area of the yard
A1=length*width=10x*15x=150x^2 yd^2
area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2
The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2
2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2
Area of the field
A2=length×width
A2=3x×6x=18x^2
Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units
