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3 years ago

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Which algebraic expression is equivalent to the expression below? 6(x - 7) + 15(x + 9) A. 21x + 8 B. 90x + 93 C. 21x + 177 D. 21

x + 93

2 answers:

WARRIOR [948]3 years ago

6 0

The Answer is D
21x+93

anastassius [24]3 years ago

3 0

The correct answer for this equation is D.

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What is the perimeter of triangle ABC ?

blagie [28]

Answer:

$9+\sqrt{41}$

Step-by-step explanation:

From C-A, it goes from y=1 to y=5, so that 4 units

From A-B, it goes from x = -1 to x = 4, that is 5 units

Now, to find distance from B to C, we need to use the distance formula:

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Where the variables are the respective points of B and C,

B (4,5) & C(-1,1)

So x_1 =4, y_1=5, x_2=-1, y_2=1

Plugging into the formula we get:

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\D=\sqrt{(1-5)^2+(-1-4)^2}\\D=\sqrt{16+25}\\ D=\sqrt{41}$

Summing it all (perimeter is sum of 3 sides):

Distance = $4+5+\sqrt{41}\\ =9+\sqrt{41}$

3rd answer choice is right.

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3 years ago

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algol13

Answer:

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Step-by-step explanation:

you add then all together to get 5

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3 years ago

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3 years ago

Enter your answer and show all the steps that you use to solve this problem in the space provided. Find the values of x and y.

satela [25.4K]

Answer : The value of x and y is, $90^o$ and $43^oC$

Step-by-step explanation :

First we have to calculate the angle B.

As we know that,

The given triangle is an isosceles triangle in which the angles opposite to equal sides are always equal.

Thus, $\angle B=\angle C$

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$\angle B=\angle C=47^o$

$\angle B=47^o$

Now have to calculate the angle A.

As we know that the sum of interior angles of a triangle is equal to $180^o$ .

$\angle A+\angle B+\angle C=180^o$

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$\angle A+94^o=180^o$

$\angle A=180^o-94^o$

$\angle A=86^o$

Now we have to determine the angle y.

As we know that, line AD is an angle bisector. That means, it divides into two equal angles. So,

$\angle y=\frac{\angle A}{2}$

$\angle y=\frac{86^o}{2}$

$\angle y=43^o$

Now we have to determine the angle x.

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$\angle y+\angle B+\angle x=180^o$

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$\angle x=90^o$

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