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Basile [38]
4 years ago
8

Complete the square to solve the equation below. x2 + x + 7/4 HELP PLEASE

Mathematics
2 answers:
JulsSmile [24]4 years ago
6 0

Answer:

um here

Step-by-step explanation:

Fantom [35]4 years ago
3 0

Answer:

Step-by-step explanation:

x^2-x=7/4. x2−x=74 x 2 - x = 7 4.

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Answer:

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Step-by-step explanation:

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If tan theta= 3/4 , find csc theta
dangina [55]

Answer:

csc\theta=\frac{5}{3}

Step-by-step explanation:

Given:

tan\theta =\frac{3}{4}

cot\theta =\frac{4}{3}                 [∵ cot\theta =\frac{1}{tan\theta} ]

Squaring both sides.

cot^2\theta =\frac{4^2}{3^2}=\frac{16}{9}

csc^2\theta -1=\frac{16}{9}        [∵ cot^2\theta =csc^2\theta-1] ]

Adding 1 to both sides.

csc^2\theta -1+1=\frac{16}{9}+1

csc^2\theta =\frac{16}{9}+1

csc^2\theta=\frac{16}{9} +\frac{9}{9}     [Taking LCD=9 and adding fractions ]

csc^2\theta=\frac{16+9}{9}

csc^2\theta=\frac{25}{9}

Taking square root both sides.

\sqrt{csc^2\theta}=\sqrt{\frac{25}{9}}

∴ csc\theta=\frac{5}{3}

6 0
3 years ago
A 30-60-90 triangle with a hypotenuse of 6 . Find the length of all other sides
andrew-mc [135]
1.  Find the "opposite side," if the angle is 60 degrees and the hyp is 6:
     
                            opp        opp      sqrt(3)
      sin 60 deg = ------- = -------- = ----------
                            hyp          6             2

      Cross-multiplying, 2(opp) = 6sqrt(3), so that opp = 3 sqrt(3) (answer)

2.  Use the Pyth. Thm. to find the "adjacent side:"

       [3sqrt(3)]^2 + x^2 = 6^2, or 9(3) + x^2 = 36, or x^2 = 9, or x = 3.

        

The lengths of the legs of this 30-60-90 triangle are 3 and 3 sqrt(3).

check:  Does 3^2 + [3sqrt(3)]^2 = 6^2?
              Does 9 + 9(3) =              6^2?   YES
8 0
4 years ago
Help please!!!!!!!!!!!
AlexFokin [52]
Angle GQK=90
GQK=GQL+LQK
90=3n+(4n-15)
n=15
Therefore angle LQK=4(15)-15
=45
6 0
4 years ago
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