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Dmitrij [34]
3 years ago
8

Richard works at an ice cream shop. Regular cones get two scoops of Ice cream: large cones get three scoops. One hot Saturday, R

ichard
scooped 234 regulas cones and 150 large cones. One scoop of ice cream is 3 ounces. A tub of ice cream weighs 10 pounds. How many tubs of ice
cream did Richard use to make the cones?
Use the conversion 1 pound 16 ounces
Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0

The total number of scoops of ice cream that Richard got from the tub is,

 (234 regular cones) x (2 scoops / 1 regular cone) + (156 large cones) x (2 scoops / 1 large cone) = 936 scoops

Given that each scoop weighs 3 ounces, the total weight of the ice cream is 2808 ounces. For the number of tubs,

        (2808 ounces) x (1 lb / 16 ounces) x (1 tub /10 lb) = 17.55

Thus, the answer is 18.

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BRAINLIEST For the fastest answer<br>Hello I need help on this math question<br><br>​
Natali [406]

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D

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The PERIMETER will be 4/5 of the original if you reduce the sides by 4/5

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2 years ago
you earn 10 points for every coin you collect in a video game. then you find a star that triples your score. write and simplify
Tomtit [17]

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The required expression for total number of points you earn is P=10c+3p.

Step-by-step explanation:

Consider the provided information.

Let c represents the coin and p represents the points before getting star.

You earn 10 points for every coin you collect in a video game.

p=10c......(1)

You find a star that triples your score.

star=3p

Now the total number of points you earn is(P):

P=10c+3p

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5 0
4 years ago
In a rural area, only about 30% of the wells that are drilled find adequate water at a depth of 100 feet or less. A local man cl
Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

Given that in a rural area, only about 30% of the wells that are drilled find adequate water at a depth of 100 feet or less.

The sample size n = 80

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Sample proportion = \frac{27}{80} =0.3375

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b) Assumptions: Each trial is independent and np and nq >5

c) Z test can be used.

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p value = 0.233

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