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BigorU [14]
2 years ago
14

Here are measurements (in millime- ters) of a critical dimension on an SRS of 16 of the more than 200 auto engine crankshafts pr

oduced in one day: 224.120 224.001 224.017 223.982 223.989 223.961 223.960 224.089 223.987 223.976 223.902 223.980 224.098 224.057 223.913 223.999 (a) Construct and interpret a 95% confidence interval for the process mean at the time these crankshafts were produced.
Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
3 0

Answer:

(23.97, 24.03)

Step-by-step explanation:

Given the data:

224.120 224.001 224.017 223.982 223.989 223.961 223.960 224.089 223.987 223.976 223.902 223.980 224.098 224.057 223.913 223.999

Confidence interval = m ± Zcritical(s/√n)

n = sample size = 16

Zcritical at 95% = 1.96

Using calculator :

Sample mean, m = 224.0019

Standard deviation, s = 0.0618

Lower bound : 24.0019 - 1.96(0.0618/√16) = 23.971618

Upper bound : 24.0019 + 1.96(0.0618/√16) = 24.032182

(23.97, 24.03)

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The LCM of the given numbers have been determined.

<h3>What is LCM ?</h3>

LCM stands for Least Common Multiple .

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It is asked to determine

LCM of 6 and 9

6 = { 6 , 12 , 18 , 24 , 30 , 36 , 42 .....}

9 = { 9 , 18 ,27 .....}

The LCM of 6 , 9 is 18

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The LCM of 8 and 12 is 24

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4 = {4 , 8 , 12 , 16 , 20,24,28 ....}

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The LCM of 4,6 and 8  is 24

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The LCM of 20 and 30 is  60

The LCM of 25,30 and 75 is 150

The image of the solution is attached .

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brainly.com/question/20739723

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