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2 years ago

Plz help I dont get it

Mathematics

1 answer:

mamaluj [8]2 years ago

8 0

Answer:

Step-by-step explanation:

The required answer but,i may be wrong.

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1. SOCCER Suppose a youth soccer field has a

padilas [110]

Answer:

L = 100

W = 60

Step-by-step explanation:

2L + 2W = 320

-2L + 2W = -80

4W = 240

W = 60

L - W = 40

L - 60 = 40

L = 100

6 0

2 years ago

How are the functions y = x and y = x+ 5 related? How are their graphs related?

sesenic [268]

Answer:

Step-by-step explanation:

the graph gets translated 5 units above its parent graph of y = x

6 0

2 years ago

22. What is the average rate of change over the interval (-3, 2)? SEE EXAMPLES

ivann1987 [24]

The average rate of change over the interval (-3, 2) is 1

<h3>Average rate of change</h3>

The average rate of change of a function, graph, table or ordered pair is simply the slope of the relation

<h3>Interval</h3>

The interval is given as: (-3,2)

From the graph, we have:

f(-3) = -5
f(2) = 0

So, the average rate over these intervals is calculated as:

$m = \frac{f(b) - f(a)}{b -a}$

This gives

$m = \frac{f(-3) - f(2)}{-3 -2}$

Substitute known values

$m = \frac{-5- 0}{-3 -2}$

Simplify

$m = \frac{-5}{-5}\\\\$

$m =1$

Hence, the average rate of change is 1

Read more about average rate of change at:

brainly.com/question/8728504

4 0

2 years ago

PLEASE PLEASE ANSWER!

muminat

The area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = $\frac{1}{2}\times \pi r^2$

$$=\frac{1}{2}\times \pi\times 4^2$

$$=\frac{1}{2}\times \pi\times 16$

Area of the semi-circle = $$8\pi$ cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

$AC^2+BC^2=AB^2$

$AC^2+4^2=8^2$

$AC^2=64-16$

$AC^2=48$

$AC=4\sqrt{3}$ cm

Base of the triangle ABC = $4\sqrt{3}$ cm

Height of the triangle = 4 cm

Area of the triangle ABC = $\frac{1}{2}\times b \times h$

$$=\frac{1}{2}\times 4\sqrt{3} \times 4$

Area of the triangle ABC = $8\sqrt{3}$ cm²

Area of the shaded region

= Area of the semi-circle – Area of the triangle ABC

= $$8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2$

= $$8(\pi \ -\sqrt{3})\ \text{cm}^2$

Hence the area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

3 0

2 years ago

Two angle measures of a triangle are given what is the third angle measure 57 68 _ 90 40 __ 29 71 _

nexus9112 [7]

$Sum\ of\ angles\ in\ triangle\ is\ 180^{\circ}\\\\
57^{\circ},68^{\circ},x\\
57+68+x=180\\
125+x=180\\
x=55^{\circ}\\\\
90^{\circ},40^{\circ},x\\
90+40+x=180\\
130+x=180\\
x=50^{\circ}\\\\29^{\circ},71^{\circ},x\\
29+71+x=180\\
100+x=180\\x=80^{\circ}$

3 0

2 years ago