1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
oksian1 [2.3K]
3 years ago
10

Give reason:

Chemistry
1 answer:
Greeley [361]3 years ago
8 0

Answer:

it is 3

Explanation:

You might be interested in
Tool that can be used to find direction of magnetic field
olga55 [171]
A simple magnetic compass can be used
6 0
4 years ago
(a) How many stereoisomers are possible for 4,4-dimethyl-1,2-cyclopentanediol?
Monica [59]

Answer:

(a) 4 stereoisomers: (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. (b) (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol (c) No, they are optically inactive.

Explanation:

(a) The stereoisomers possible for 4,4-dimethyl-1, 2-cyclopentanediol are (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. Their structures are shown in the attached file.

(b) The oxidation reaction that occurs between 4,4-dimethylcyclopentene and osmium tetroxide produces (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol. Their structures are also shown in the attached file.

(c) The products of the oxidation reaction in (b) are optically inactive because the compounds contain plane of symmetry that makes them optically inactive compound.

Download docx
5 0
4 years ago
PLEASE HELP ME WITH THE QUESTION IN THE IMAGE AND I WILL MARK AS BRAINLIEST IF CORRECT
ASHA 777 [7]

Answer:

1. absorbs and re-emits infrared radiation

2.three or more atoms in a molecule

Explanation:

research, lots of research.

5 0
3 years ago
The weather in Europe was unusually warm during the summer of 1995. The TV news reported temperatures as high as 45 degree centi
Tpy6a [65]

Answer : The temperature on the Fahrenheit scale was, 113^oF

Explanation :

The conversion used for the temperature from degree centigrade to Fahrenheit is:

^oF=(^oC\times \frac{9}{5})+32

where,

^oF = temperature in Fahrenheit

^oC = temperature in centigrade

As we are given the temperature in degree centigrade is, 45

Now we have to determine the temperature in Fahrenheit.

^oF=(45^oC\times \frac{9}{5})+32

^oF=113

Therefore, the temperature on the Fahrenheit scale was, 113^oF

5 0
4 years ago
What pH must organisms maintain?
Ivan
The pH value indicates the degree of acidity or alkalinity of a solution. In this case, the human body fluids. When the value is 0, the pH is acid, it is 14, we speak of an alkaline pH, and 7 indicates a neutral value. Inside the body, the pH may vary according to the body, and the specialists argue that do not have to be the same everywhere.
8 0
3 years ago
Other questions:
  • A sample of radium-226 contains 1.0×108 atoms of radium-226. How many atoms of radium-226 will remain in the sample after three
    5·1 answer
  • What volume of air at 0.98 atm can be compressed into an 11.1 L scuba air tank if the tank is pressurized to 204 atm?
    9·1 answer
  • What is NaH2????????
    14·1 answer
  • What determines the life cycle of a star
    7·1 answer
  • Which device involves the use of plasma in technology
    7·2 answers
  • What are the main functions of estrogen and progesterone during the
    15·1 answer
  • Which safety feature works to slow down nuclear-fission chain reactions?
    7·2 answers
  • Which of the following describes a chemical reaction?
    7·1 answer
  • Why you get scratches on your skin if you move your nails against it
    8·1 answer
  • Covalent bonds in a molecule absorb radiation in the IR region and vibrate at characteristic frequencies.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!