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mihalych1998 [28]
3 years ago
14

Solve this system of equations.

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
4 0

Answer:

<em>x = -3 and y = 0</em>

Step-by-step explanation:

<em>It would be more direct to apply elimination in this problem, rather than substitution:</em>

  2x + 6y = -6       ⇒      2x + 6y = -6       ⇒      10x = - 30

+ 2(4x - 3y = -12)        +  8x - 6y = -24

<em>Now let us solve for x through simply algebra:</em>

10x = -30,

  <em>x = -3</em>

<em>Substitute this value of x into the first equation to get the value of y:</em>

2( -3 ) + 6y = -6,

-6 + 6y = -6,

  6y = 0,

    <em>y = 0</em>

nasty-shy [4]3 years ago
3 0

Answer:

-3 and 0

Step-by-step explanation:

i hope this helps :)

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3 years ago
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Answer:

Option (C)

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Now we substitute these values in the formula,

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4 years ago
GIVING THE BRAINLIEST ANSWER
Ahat [919]

Answer:

(6,3)

Step-by-step explanation:

y=2/3 x - 1

y=-1/2 x + 6

Since both equations are equal to y, we can set them equal

2/3 x - 1 =-1/2 x + 6

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6(2/3 x - 1) =(-1/2 x + 6)6

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3 years ago
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