3 years ago

The higher the value of the coefficient of friction , the blank the resistance to sliding

Advanced Placement (AP)

1 answer:

cestrela7 [59]3 years ago

3 0

Answer:

higher

Explanation:

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Answer:

$156.1^{\circ}C$

Explanation:

We can solve the problem by using Gay-Lussac's law, which states that:

"For a fixed mass of ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"

Mathematically:

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where

p is the pressure

T is the absolute temperature

The equation can be also rewritten as

$\frac{p_1}{T_1}=\frac{p_2}{T_2}$

where, in this problem:

$p_1 = 53.0 Bar$ is the initial pressure

$p_2=35.2 Bar$ is the final pressure

$T_2=12.0^{\circ}+273=285 K$ is the final temperature

Solving for T1, we find the initial temperature:

$T_1=\frac{p_1 T_2}{p_2}=\frac{(53.0)(285)}{35.2}=429.1 K$

Converted into Celsius degrees,

$T_2=429.1-273=156.1^{\circ}C$

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