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Zarrin [17]
3 years ago
13

Plz help me with it

Mathematics
2 answers:
Radda [10]3 years ago
8 0
<h3>5 should be the answer I hope</h3>
Morgarella [4.7K]3 years ago
8 0

Answer:   5

<u>Step-by-step explanation:</u>

\sqrt{4x+5}-\sqrt{x-1}=\sqrt{x+4}\\\\(\sqrt{4x+5}-\sqrt{x-1})^2=(\sqrt{x+4})^2\\\\4x+5-2\sqrt{(4x+5)(x-1)}+x-1=x+4\\\\5x+4-2\sqrt{(4x+5)(x-1)}=x+4\\\\4x=2\sqrt{(4x+5)(x-1)}\\\\2x=\sqrt{(4x+5)(x-1)}\\\\(2x)^2=(\sqrt{(4x+5)(x-1)})^2\\\\4x^2=(4x+5)(x-1)\\\\4x^2=4x^2+x-5\\\\0=x-5\\\\5=x\\\\\\Check:\\\sqrt{4(5)+5}-\sqrt{(5)-1}=\sqrt{(5)+4}\\\\\sqrt{25}-\sqrt{4}=\sqrt9\\\\5-2=3\ \checkmark

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<u>Given</u>:

The length of DE is 8 cm and the measure of ∠ADE is 60°.

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<u>Length of AD:</u>

The length of AD is given by

cos 60^{\circ}=\frac{FD}{8}

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Length of AD = 8 cm

<u>Slant height:</u>

The slant height EF can be determined using the trigonometric ratio.

Thus, we have;

     sin \ 60^{\circ}=\frac{EF}{8}

sin \ 60^{\circ} \times 8=EF

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The surface area of the square pyramid can be determined using the formula,

SA=Area \ of \ square + \frac{1}{2} (Perimeter \ of \ base ) (slant \ height)

Substituting the values, we have;

SA=8^2+\frac{1}{2}(8+8+8+8)(4 \sqrt{3})

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SA=64+(16)(4 \sqrt{3})

SA=64+64 \sqrt{3}

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