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2 years ago

A cube with the number 1,2, 3, 4, 5 and 6; what is the probability of getting an even number?

Mathematics

1 answer:

mr Goodwill [35]2 years ago

6 0

Step-by-step explanation:

answer is one and half

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I need help with this please

Ierofanga [76]

C is the correct answer

we should find the area of the square and then divide it by 24.
(360/15=24)

$6 \times 6 \times \pi \times \frac{1}{24} = 36 \times \pi \times \frac{1}{24} \\ = 113.04 \times \frac{1}{24} = 4.71$

good luck

8 0

3 years ago

Read 2 more answers

Rashid has one dollar.he wants to buy a ball for 50 cents. he also wants to buy two other toys and still have money left over. e

Alex777 [14]

Answer:

He needs to makes sure both equal to 0.50 or less

Step-by-step explanation:

8 0

3 years ago

The numerator of a certain fraction is four times the denominator. If 10 is added to both numerator and denominator the resultin

Ronch [10]

20/5 4x/x adding 10 to each 4x+10/x+10 =2 Multiple x+10 to each side 4x+10=2x+20 Then subtract and get 2x=10 Divide X=5 Now plug it back in 20/5

7 0

3 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago

If PQ=8 and Q lies at -13 where could P be located?

choli [55]

Answer:

In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).

Step-by-step explanation:

There is really no need to use any quadratics or roots.

( Consider the same problem on the plain number line first. )

How do you find the number between 2 and 5 which is twice as far from 2 as from 5?

You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get

4=2+23(5−2)

It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then

R=P+23(Q−P)

so in your case we get

R=(0,−1)+23(3,3)=(2,1)

Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)

Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get

s=a+b=2b+b=3b

⇔b=13s⇒a=23s

7 0

3 years ago