<span>The factors of 60 are 60, 30, 20, 15, 12, 10, 6, 5, 4, 3, 2, 1.The factors of 75 are 75, 25, 15, 5, 3, 1.<span>The common factors of 60 and 75 are 15, 5, 3, 1, intersecting the two sets above.</span><span>In the intersection factors of 60 ∩ factors of 75 the greatest element is 15.</span><span>Therefore, the greatest common factor of 60 and 75 is 15.
</span></span>
The phrase "annual" ("the company was able to enjoy yearly electricity") is sufficient to convey that the savings happened every year, so D is the optimal response.
<h3>What Are Savings?</h3>
Savings are the funds that remain after subtracting a person's consumer spending from their disposable income during a specific time period. Savings, then, is what's left over after all bills and commitments have been fulfilled for an individual or household. Cash or cash equivalents (such as bank deposits) are used to store savings since they carry no danger of loss but also offer very low returns. Savings can increase through investing, but doing so involves putting money at risk.
To learn more about Savings, visit:
brainly.com/question/10749354
#SPJ4
Answer:
B. 5
Step-by-step explanation:
- |3 - 5 + 7|=
- |- 2 + 7 | =
- | 5 | =
- 5
<u>Answer is</u>: B. 5
Answer:
(1) the account number and (2) the journal page number.
Step-by-step explanation:
A posting reference column helps to establish interlinking between a journal and a ledger.
In a journal this indicates the account number to which the entry has been posted.
Whereas in a ledger, it indicates the page of the journal in which the entry can be found.
So, the correct option is : D.
(1) the account number and (2) the journal page number.
Answer:
Step-by-step explanation:
A function is one-to-one if it passes the horizontal line test. This is the case if a horizontal line intersects the graph in only one place.
The graph of f(x) = x^2 - 5 is that of a parabola that opens upward. There are several possibilities here:
1. The horizontal line intersects the parabolic graph twice on the interval (-infinity,+infinity). Therefore this function is not one-to-one on this interval
(-infinity,+infinity).
2. If we define the domain as [0,+infinity), a horizontal line will intersect this parabolic graph only once. Therefore this function is one-to-one on [0,+infinity).