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2 years ago

5

3.Lou has the first 4 encyclopedias lined up on a shelf, A, B, C, and D. If he picks two at random, what is the probability that

he picks A first and B second?

1 answer:

Oksana_A [137]2 years ago

8 0

Because they are first.

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* Use for question 4-6 *

rusak2 [61]

16ft.(.25s)2
4ft/s*2
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16ft(.5s)2
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16ft/s

16ft(2s)2
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64ft/s

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3 years ago

What is the product of -5 and 8?<br> -40<br> О -13<br> 013<br> О 40

Alexeev081 [22]

Answer:

13

Step-by-step explanation:

this would be 13

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2 years ago

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A scatter plot containing the point (5,9) has the regression equation y = -x-3 (see photo)

Tatiana [17]

The residual is the difference between the plotted point and the line of best fit.

We first need to know the point at x=5 for the line of best fit.
y1 = -(5) - 3 = -8

Now we need to find the difference between the line of best fit and the plotted point.
residual = 9 -(-8) = 9 + 8 = 17 or C

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3 years ago

75=6·w<br> the solution is w=?

Ber [7]

I think answer should be 450 please give me brainlest let me know if it’s correct or not okay thanks bye

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2 years ago

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Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

6 0

2 years ago