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Tems11 [23]
3 years ago
15

2x + 9 8x + 1 Solve for x

Mathematics
1 answer:
Leto [7]3 years ago
8 0
2x+9+8x+1=180

2x+8x+9+1=180

10x+10=180

10x=170

X=17
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Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. A car repair center services 920 cars in 2012. Th
OverLord2011 [107]

Answer:

N = 920(1+0.03)^4t

Step-by-step explanation:

According to the given statement a car repair center services 920 cars in 2012. The number of cars serviced increases quarterly at a rate of 12% per year after 2012.

Rate is 12 % annually

rate in quarterly = 12/4= 3%

We will apply the compound interest equation:

N=P( 1+r/n)^nt

N= ending number of cars serviced.

P=  the number of cars serviced in 2012,

r = interest rate

n = the number of compoundings per year

t= total number of years.

Number of compoundings for t years = n*t = 4t

Initial number of cars serviced=920

The quarterly rate of growth = n=4

r = 3%

The growth rate = 1.03

Compound period multiplied by number of years = 920(1.03)^4t

Thus N = 920(1+0.03)^4t

N = number of cars serviced after t years...

5 0
3 years ago
What are the answer to these questions:
Tomtit [17]
1. 40/60 + 15/60 + 24/60 + 10/60 = 1.48

2.30/60 + 20/60 + 15/60 + 12/60 + 10/60 = 1.45
3 0
3 years ago
Can someone please tell me the answer and explain how to do this, no links please thank you
avanturin [10]
<h2>If this is work out the gradient then here:</h2>

Step-by-step explanation:

3-0= 3

2-(-2)= 4

3/4= 0.75

<h3>Equation of a gradient is </h3><h2>\frac{y^2-y^1}{x^2-x^1}</h2>
7 0
3 years ago
For the function Y=5x, what would happen if the value 5 was changed to 3
Daniel [21]

Answer:

y = 3 * x

Step-by-step explanation:

We have the function y = 5 * x, they ask us what would happen if we change the 5 by the 3. thus:

y = 3 * x

the constant that accompanies x in this case is an increase or slope constant, that is, now x will not increase by a ratio of 5, but by a ratio of 3. For example:

If x were worth 10

the value before was 50 and now it will be 30.

I do not increase 5 times but 3 times.

4 0
4 years ago
Laser scanning for fish volume estimation. engineers design tanks for rearing commercial fish to minimize both the use of natura
AVprozaik [17]

Answer:

The 99% confidence interval would be given by (196.2;283.8)

We are 99% condident that the true mean is between 196.2 and 283.8  

We need to assume that the data comes from a random sample and we need to assume that the distribution of the data is normal.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=240 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=15 represent the sample standard deviation

n=4 represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=4-1=3

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,3)".And we see that t_{\alpha/2}=5.84

Now we have everything in order to replace into formula (1):

240-5.84\frac{15}{\sqrt{4}}=196.2    

240+5.84\frac{15}{\sqrt{4}}=283.8

So on this case the 99% confidence interval would be given by (196.2;283.8)    

We are 99% condident that the true mean is between 196.2 and 283.8

What assumption about the data is necessary for the inference derived from the analysis to be valid?

We need to assume that the data comes from a random sample and we need to assume that the distribution of the data is normal.

4 0
3 years ago
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