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Neko [114]
3 years ago
7

Is anyone else eating Cheetos?

Mathematics
2 answers:
tamaranim1 [39]3 years ago
8 0

Answer:

yeah

Step-by-step explanation:

i am

Anarel [89]3 years ago
7 0

Answer:

not meeee

Step-by-step explanation:

giv brainliest pls

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2. Four friends share 3 apples equally.
Slav-nsk [51]

Answer:

1/3

Step-by-step explanation:

Each friend gets 1/3 of an apple

5 0
3 years ago
In archery I need to know what is the box plot for sagars scores
Anit [1.1K]
<span>I think you know by now that I strongly encourage everyone to shoot a proper round and whatever the score is, to submit it to our Records Officer, Giles Conn. Think of it as an annual competition (a) to wear him out, and (b) to see if we can altogether, beat last year's tally. Also, for the outdoor season rounds, you can have a go at achieving the St Wilfred trophy. I've won it 3 years running (last year jointly with Terry Skinner), but they wouldn't let me keep it this time, sadly.</span>
6 0
3 years ago
During the month of febuary fabulous feet shoe mart sold 48 pairs of red loafers. After an ad campaign to boost sales they sold
frutty [35]
The percent of increase in sales.
(60-48)/48)*100=25%
7 0
3 years ago
The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =
gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy  is given as :

f_x(x)  = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0

Thus, the expected  total claim amount \mu =  1000

The variance of the total claim amount \sigma ^2  = 1000^2

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})

P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})

P(X>1100n) = P(Z> \dfrac{10*100}{1000})

P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345

\mathbf{P(X>1100n) = 0.158655}

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

4 0
3 years ago
Question: if Cory walks 3 units south and 4 units east, what would his new coordinate be?
maks197457 [2]

Answer:

(5,-2).

_______________________

South is Negative Y axis.

East is Positive X axis.

(look at the compass in the top right corner)

Cory's current coordinates are (1,1).

When Cory walks 3 units south, he moves 3 steps downwards in the Y axis, which means if his current Y position is 1, we subtract 3, ( 1 - 3 = -2).

And when Cory moves 4 units east, Add 4 as he is walking in the positive X axis. (4 + 1 = 5).

new (x,y) are (5,-2).

7 0
2 years ago
Read 2 more answers
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