Answer:
Step-by-step explanation:
We have:
And we want to find the value of x such that the expression is positive. So, we can write this as the following inequality:
Solve for the inequality. First, we can solve for the zeros like a normal quadratic. So, pretend the inequality is with an equal sign:
Zero Product Property:
On the left, subtract 5.
On the right, add 1.
So, our zeros are:
Since our inequality is a <em>greater than</em>, our answer is an "or" inequality with our answer being all the values to the <em>left</em> of our lesser zero and all the values to the <em>right </em>of our greater zero.
So, our solution is:
And we're done!
Hmm, one way we can do this is by assigning numbers to each
A=4 and B=3
A>B because 4>3
so
A. 2(A+B)=2(4+3)=2(7)=14
B. A+B^2=4+3^2=4+9=13
C. A^2+B^2=4^2+3^2=16+9=25
D. A^2-B^2=4^2-3^2=16-9=7
the largest is 25 so C
Answer:
And the 96% confidence is given by (110.06; 117.34)
Step-by-step explanation:
Information given
represent the sample mean
population mean (variable of interest)
s=9.1 represent the sample standard deviation
n=29 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
(1)
The degrees of freedom are given by:
The Confidence is 0.96 or 96%, the significance is 
and 
, and the critical value would be 
Replacing the info we got:
And the 96% confidence is given by (110.06; 117.34)
A is the correct answer
good luck
Answer:
p=0.25
Step-by-step explanation:
Given that a club can select one member to attend a conference. All of the club officers want to attend. There are a total of four officers, and their designated positions within the club are President (P), Vice dash President (Upper V )comma Secretary (Upper S )comma nbspand Treasurer (Upper T ).
Sample space would be
a){ {P}, {V}, {S} {T}} is the sample space with notations standing for as given in the question
b) Each sample is equally likely. Hence we have equal chances for selecting any one out of the four.
If probability of selecting a particular sample of size I is p, the by total probability axiom we have
\begin{gathered}4p =1\\p =0.25\end{gathered}
4p=1
