find the average of the numbers 5/8, 9/10, 2 3/4 write the solution as a mixed number or fraction in lowest terms.

Calculate the derivative of the following function. y=e6x(6x+1)5

netineya [11]

Answer:

Y' = 360ex+ 30e

Step-by-step explanation:

Y=e×6x×(6x+1) × 5

y'= d/dx (e×6x ×(6x+1)×5)

y'=d/dx(30ex ×(6x+1))

y'=d/dx(180ex^2 + 30ex)

y'=d/dx(180ex^2) + d/dx (30ex)

Calculate the derivative

y'=180e×2x +30e

y'=360ex+30e

6 0

3 years ago

elise bought 5 boxes of cereal and 2 gallons of milk for a total cost of $31.24 each box of cereal cost $ 4.80 enter the cost in

vitfil [10]

Answer:

7.24

Step-by-step explanation:

Multiply 5 boxes of cereal by the cost of cereal

31.24 minus that number gives the answer

6 0

3 years ago

The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv

Rina8888 [55]

Answer:

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=14.42$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=6.95$ represent the population standard deviation

n=36 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$