3 years ago

Will give brainliest answer

Mathematics

2 answers:

kiruha [24]3 years ago

8 0

Answer:

The answer is C

laiz [17]3 years ago

5 0

Answer is C :):):) hope it’s right

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Two consecutive perfect squares have a difference of $99$. what is the value of the larger perfect square?

Fofino [41]

Answer:

2500

Step-by-step explanation:

Let the first square number be $x^2$ then the next square number is $(x+1)^2$ .

The difference between these two consecutive numbers is 99.

This implies that:

$(x+1)^2-x^2=99$

We expand to get:

$x^2+2x+1-x^2=99$

Simplify:

$2x=99-1$

$2x=98$

Divide both sides by 2

$x=49$

Therefore the value of the larger perfect number is

$(49+1)^2=50^2=2500$ .

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Step-by-step explanation:

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Vesnalui [34]

Answer:

Step by Step:
x-2y=4
+2y +2y
x=-2y+4

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Divid by 2
1/2x-2= y

x=-2y+4
x=-2(1/2x-2)+4
x=-x+4+4
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y=1/2(4)-2
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