Answer:
P(O and O) =0.1296
P=0.3778
Step-by-step explanation:
Given that
blood phenotypes in a particular population
A=0.48
B=0.13
AB=0.03
O=0.36
As we know that when A and B both are independent that
P(A and B)= P(A) X P(B)
The probability that both phenotypes O are in independent:
P(O and O)= P(O) X P(O)
P(O and O)= 0.36 X 0.36 =0.1296
P(O and O) =0.1296
The probability that the phenotypes of two randomly selected individuals match:
Here four case are possible
So
P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)
P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36
P=0.3778
10. x*x + 10x + 21 = x + 3 * length
11. x*x + 2x - 8 = x + 4 * breadth
This is the expression bro!
100% sure
Plz mark me brainliest
Answer:
Yes, they are equivilant
Step-by-step explanation:
5(3m+2p)-4m = 13p+11m-3p
Distribute 5: 15m+10p-4m = 13p+11m-3p
Combine like terms: 15m+(-4m) = 11m ; 13p+(-3p) = 10p
11m+10p = 11m+10p
I know for a fact B is wrong, so you can mark that off. I got C.