The answer is 7/12,3/4,5/6
Remark
First of all, you should notice that the number you want must end in 5 to get a remainder of 5. That's because your divisors all end in 0.
Step One
Factor the 3 divisors
40: 2 * 2 * 2 * 5
50: 2 * 5 * 5
60: 2 * 2 * 3 * 5
Step Two
Using these factors, find the LCM
There are 3 twos, 1 Three, and 2 fives.
The LCM is 8*3*25 = 600
Step Three
Find the first number over 1000 that is divisible by 600. That should be 1200 which is 600 * 2
So the answer to your question is 1205
Quadrant I : cot(x) > 0 → -cot(x) < 0
Quadrant II : cot(x) < 0 → -cot(x) > 0
Quadrant III : cot(x) > 0 → -cot(x) < 0
Quadrant IV : cot(x) < 0 → -cot(x) > 0
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Answer: a)

We know that one answer is only true, so we did not check the correctness of the cotangent value, only to the number sign
Answer:
20
Step-by-step explanation:
f(x) = x + 10
Replace f(x) with y.
y = x + 10
Now, remember that in an inverse function you flip the x and y, so
x = y + 10
Solve for y
y = x - 10
because it's 2x... we must multiply by 2.
2y = 2x - 20
Original equation:
h(x) = 2x - 0
h(x) is 2y..
D.
Answer:
x=6
Step-by-step explanation:
We can write this as a ratio
x 9
---- = --------
10 15
Using cross products
15x = 10*9
15x = 90
Divide by 15
15x/15 = 90/15
x =6