Hello :
by idetity : 1+cos(2a) = 2cos²(a)
let : a = <span>θ/2
1+cos(2×</span>θ/2)=2cos²(θ/2)
1+cos(θ) = 2cos²(θ/2)
solve : 2 cos^2 (θ/2) - 3 cos(θ) = 0 ......(1)
(1) : 1+cos(θ)-3 cos(θ) =0
2cos(θ) = 1
cos(θ) = 1/2
in : [0, 2π<span>[
</span>( θ = π/3) or (θ = 5π/3)
Answer:
2/3.
Step-by-step explanation:
.
Answer:
Step-by-step explanation:
g(m) = 0
2-4m=0
2=4m
2/4=m
1/2=m------(1
p(1/2)= -3(1/2) - { 2(1/2) + (5- 1/2) } +7
= -3/2 - { 1 + 9/2} +7
= -3/2 - ( 11/2) +7
=-14/2 +7
= -14 + 14 /2
= 0/2
= 0...
since p(m)= 0,
we can say that g(m) is a factor of p(m)
hence, it has been simplified correctly...
Answer:
approximately 43 - 44 minutes exact
9/10 = 36/40
9/10 x 4/4 = 36/40
