3 years ago

I need help on this problem

Mathematics

1 answer:

Papessa [141]3 years ago

4 0

Step-by-step explanation:

${f}^{ - 1} (x) = x \: value$

$f(x) = \sqrt[4]{x} + 6 \\$

$x - 6 = \sqrt[4]{x}$

${(x - 6)}^{4} = x$

${f}^{ - 1}(x) = {(x - 6)}^{4}$

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