Answer:
constant acceleration of 9.81 m/s^2 against the weight of the person standing in spaceship.
Explanation:
- At earth surface we would feel a gravitational pull of g = 9.81 m/s^2 downwards.
- For anyone on spaceship to feel the same pull the spaceship needs to accelerate upwards at a constant acceleration of a = 9.81 m/s^2.
- The effect of "weightlessness" is removed such that the contact force between the person on the space-ship and the person him or herself is equal to the apparent weight of the person.
- If the spaceship accelerates constantly at 9.81 m/s^2, the apparent weight of the person would equal the actual weight on earth.
what country was once the crown jewel of the spanish empire?
About 1.1 miles long Or 5,989 feet
