Answer:
P = 1 / 6
Step-by-step explanation:
Given:-
- A deck has 500 cards
- Numbered from 1-500
Find:-
you are asked to pick three cards, one at a time, what's the probability of each subsequent card being larger than the previous drawn card
Solution:-
- Suppose we draw three cards. We don't care what they actually are, irrespective of number.
- Let the three numbers be a, b, c: Such that:
a < b < c.
- The total possible combinations with 3 numbered cards will be:
a b c
b a c
a c b
b a c
b c a
c a b
- We have 6 possibilities for 3 numbered cards. So the probability of of each subsequent card being larger than the previous drawn card would be:
P = 1 / possible combinations
P = 1 / 6
Combine q terms
-30 = 12q - 10
Add 10 to both sides
-20 = 12q
Simplify
Q = -5/3
Answer:
x = 24
Step-by-step explanation:
Pythagorean Theorem: a² + b² = c²
<em>a</em> = a leg
<em>b</em> = another leg
<em>c</em> = hypotenuse
Step 1: Plug in known variables
x² + 10² = 26²
Step 2: Evaluate
x² + 100 = 676
Step 3: Isolate <em>x </em>term
x² = 576
Step 4: Isolate <em>x</em>
√x² = √576
x = 24
Answer:
A) -p + 38
B) k + 1
C) a_n = 4n + 1
D) a_n = 7n - 6
E) a_n = 14 - 4n
Step-by-step explanation:
A) 5(p + 6) - 2(3p + 4)
Multiply out the bracket to get;
5p + 30 - 6p + 8
>> -p + 38
B) 7(k - 2) - 3(2k - 5)
Multiply out the bracket to get;
>> 7k - 14 - 6k + 15
>> k + 1
C) Sequence is;
5, 9, 13, 17, 21
This is clearly an AP(arithmetic progression) because the difference between each term is 4.
Formula for nth term of an AP is;
a + (n - 1)d
Where d is difference and a is first term
Thus;
a_n = 5 + (n - 1)4
a_n = 5 + 4n - 4
a_n = 4n + 1
D) Sequence is 1, 8, 15, 22, 29.
This is also an AP.
Difference is 7.
Thus,nth term is;
a_n = 1 + (n - 1)7
a_n = 1 + 7n - 7
a_n = 7n - 6
E) 10, 6, 2, -2, -6
This is also an AP.
Difference is -4
Thus,
a_n = 10 + (n - 1)(-4)
a_n = 10 - 4n + 4
a_n = 14 - 4n
