Question

y is inversely proportional to x^2, and y = 540 for a particular value of x. Find the value of y when this value of x is tripled.

Answer 1

Step-by-step explanation:

$y = \frac{1}{ 3{x}^{2} } \\ y = 540 \\ 540 = \frac{1}{3 {x}^{2} } \\ 3 {x}^{2}(540) = 1 \\ 3 {x}^{2} = \frac{1}{540} \\ {x}^{2} = \frac{1}{540} \div 3 \\ {x}^{2} = \frac{1}{540} \times \frac{1}{3} \\ {x}^{2} = \frac{1}{1620} \\ x = \sqrt{ \frac{1}{1620 } } \\ x = 0.024845$