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Gemiola [76]
3 years ago
6

Prove that:

Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0

Step-by-step explanation:

16⁴ - 2¹³ - 4⁵

= 2¹⁶ - 2¹³ - 2¹⁰

= 2¹⁰(2⁶ - 2³ - 1)

= 2¹⁰(64 - 8 - 1)

= 2¹⁰ * 55

= 2¹⁰ * 5 * 11.

Since it contains 11 in its prime factorization, it is divisible by 11. (Proven)

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How can I solve a multi step equation ex. 4x-9=7x+12
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First you bring the x to one side so u subtract 4x from 7x and you get the new equation as -9=3x+12 then you just solve and you get x is equal to -7
4 0
3 years ago
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Convert the following into standard form<br> Y=7/5x+1
vlabodo [156]

Answer:

7x - 5y = -5 this is the standard form

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3 years ago
What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

4 0
3 years ago
Which expression is equivalent to 3⁴ . 3-⁹
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Answer:

3^-5 or 1/3^5(b)

Step-by-step explanation:

3⁴•3^-9

When bases are same powers are to be added

So the above expression becomes

3^4+(-9)

3^4-9

3^-5

5 0
4 years ago
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Graph of the figure after the indicated translation
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After the translation performed J is now (-2,-2), M is now (-1,-4), K is now (4,1), and L is now (5,-1).

Hope this helps!

6 0
4 years ago
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