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3 years ago

For the function: y = VX-7-1 The domain is :x> The range is: y z DONE

Mathematics

1 answer:

nexus9112 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Function y = $\sqrt{x-7}$ - 1 is exist for x - 7 ≥ 0 ⇒ x ≥ 7

The domain is: x ≥ 7

If x = 7 , then $y_{min}$ = - 1

The range is: y ≥ - 1

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Please explain number 10 in a step by step process.

Aleonysh [2.5K]

Good evening ,

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Answer:

a=3

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Step-by-step explanation:

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3 years ago

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Justin recently drove to visit his parents who live 96 miles away. On his way there his average speed was 20 miles per hour fast

never [62]

Answer:

Justin's average speed to his parents' house: x= 40mph

Justin's average speed from his parents' house: x+20=60 mph

Step-by-step explanation:

Let the average speed be x +20

Then average speed from his parents' x

And the distance is S=96

Then we know :

$\displaystyle \frac{S}{x+20} +\frac{S}{x} =4 \\\\\\ \frac{96}{x+20} +\frac{96}{x}=4 \ |\div 4 \\\\\\ 24\bigg(\frac{1}{x+20} +\frac{1}{x} \bigg) =1 \\\\\\ 24\cdot \frac{x+x+20}{(x+20)x} =1 \ |\cdot (x+20)x \ \ \\\\\\48x+480=x^2+20x \\\\ x^2-28x-480=0 \\\\ \rm D=28^2+4\cdot 480=2704 =52^2 \\\\ \boxed{x_1=\frac{28+52}{2} =40} \\\\x_2=\frac{28-52}{2} =-12 \ \ \varnothing$

Justin's average speed to his parents' house: x= 40mph

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3 years ago

How many truths are in a whole? Who many hundredths?

postnew [5]

There are 10 tenths in a whole number and 100 hundredths in a whole number. (FYI there are 10 Hundredths in a tenth)

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3 years ago

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write the equation for an exponential function, in the forms y = a x b^x, whose graph passes through the coordinate points (1, 7

zysi [14]

Y = abˣ
(a ≠ 0, b ≠ 0)

(1, 7.5)
x = 1
y = 7.5
  ↓
7.5 = ab

(3, 16.875)
x = 3
y = 16.875
  ↓
16.875 = ab³

7.5 = ab
b b
7.5/b = a

  16.875 = ab³
b³ b³
16.875/b³ = a

7.5/b = 16.875/b³
7.5/b(b³) = 16.875/b³(b³)
7.5b² = 16.875
7.5 7.5
b² = 2.25
  √(b²) = √(2.25)
b = 1.5

a = 7.5/b
a = 7.5/1.5
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4 years ago

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What is the coefficient of 12a+5

butalik [34]

The coefficient is 12a because it has a variable (a).

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3 years ago

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