Answer:
see attached
Step-by-step explanation:
<h3>1.</h3>
Solid dots go at all the end points except the one at (3, 6), which gets an open dot signifying the function is not defined for that point.
For the first portion of the graph, the square root function is shifted left one unit and scaled vertically by a factor of 3.
The second portion of the graph is a line with a slope of -1. It would have a y-intercept of 5 if it were defined there. It has an x-intercept of 5.
<h3>2.</h3>
The y-intercept is found by setting x=0 and solving for y.
... y = log(2·0+1) -1 = log(1) -1 = 0 -1 = -1
The x-intercept is found by setting y=0 and solving for x.
... 0 = log(2x +1) -1
... 1 = log(2x +1) . . . add 1
... 10 = 2x +1 . . . . . . take the antilog
... x = (10 -1)/2 = 4.5 . . . . . subtract 1, divide by the x coefficient
The intercepts are (0, -1) and (4.5, 0).
Answer:
4.
Step-by-step explanation:
32.83 + 0.8 = 33.63
37.63 - 33.63 = 4.
Answer:
✓✓ Area of traingle = 1.2 cm^2 ✓✓
Step-by-step explanation:
Hello mate (◕ᴗ◕✿)
=>> In above traingle, <u>height and hypotenuse are </u><u>given</u>
<u>=</u><u>></u><u> </u><u>height</u><u> </u>= 12 cm
<u>=</u><u>></u><u> </u><u>Hypotenuse</u> = 14 cm
✓✓ <u>Area</u><u> of</u><u> </u><u>traingle </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>(</u><u>base*</u><u>height</u><u>)</u><u> </u><u>✓</u><u>✓</u>
<u> </u>we need to find base of above traingle
<u>Base </u><u>=</u><u> </u><u>√</u><u>H</u><u>y</u><u>p</u><u>o</u><u>t</u><u>e</u><u>n</u><u>u</u><u>s</u><u> </u><u>-</u><u> </u><u>√</u><u>P</u><u>e</u><u>r</u><u>p</u><u>i</u><u>n</u><u>d</u><u>i</u><u>c</u><u>u</u><u>l</u><u>a</u><u>r</u><u> </u>
Base = √14 - √12
Base = 3.7 - 3.4
Base = 0.2 cm
Now, we can find area of traingle
<u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>(</u><u>Base*</u><u>Height</u><u>)</u>
<u> </u><u> </u><u> </u><u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>1</u><u>/</u><u>2</u><u>(</u><u>0</u><u>.</u><u>2</u><u>*</u><u>1</u><u>2</u><u>)</u>
<u> </u><u> </u><u> </u><u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>6</u><u>*</u><u>0</u><u>.</u><u>2</u>
<u> </u><u> </u><u> </u><u> </u><u>Area</u><u> of</u><u> traingle</u><u> </u><u>=</u><u> </u><u>1</u><u>.</u><u>2</u><u> </u><u>cm^</u><u>2</u>
<u> </u>Hope it helps you mate (. ❛ ᴗ ❛.)
Answer:
See the picture below
Step-by-step explanation:
Well if the original population is 250 crickets after 6 months it would double to 500. After another 6 months (A year now) it would again double in size to 1000 and so on for 2 more periods of 6 months. After doubling two more times you get 4000, or answer D.