In the original set of numbers, the median is six
But, if six was added to the set, then the median would be six
So the median wouldn't decrease at all
The answer is the first one in the options
A because if you look t is on +3 and r is on -41/2
Answer: July 25th, 1980.
Step-by-step explanation: ADIOS.
\frac{d}{dx}\left(\frac{1+x^4+x^6}{x^2+x+1}\right)=\frac{4x^7+5x^6+8x^5+3x^4+4x^3-2x-1}{\left(x^2+x+1\right)^2}
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