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3 years ago

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Line v passes through point (6, 6) and is perpendicular to the graph of y = 3/4x – 11. Line w is parallel to line v and passes t

hrough point (–6, 10). Which is the equation of line w in slope-intercept form?

2 answers:

kvv77 [185]3 years ago

7 0

Answer:

-14.525

Step-by-step explanation:

i hope its correct

liq [111]3 years ago

5 0

Answer:

y= 4/3x + 2

Step-by-step explanation:

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Answer please, tysvm!

mariarad [96]

Answer: The answer Is C.

Step-by-step explanation:

If you multiply 3/4 by 4 then you will get 3.

Also B. is to big to split between four friends and A. is to small.

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3 years ago

Read 2 more answers

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

stealth61 [152]

Answer:

$M_x = 2, M_y = 3$

Center of mass at $(\frac{3}{10},\frac{2}{10})$

Step-by-step explanation:

Given a set of objects $m_1, \dots, m_k$ located at the points $P_1(x_1, y_1), \dots, P_k(x_k,y_k)$ The moments Mx and My are calculated as follows.

$M_x = \sum_{n=1}^k m_n\cdot y_n, M_y = \sum_{n=1}^k m_n\cdot x_n$

and the Center of mass is given at the coordinates $(\frac{My}{M}, \frac{Mx}{M})$ where M is the total mass of the system.

We have that m1=3, m2=4 and m3=3, so M = 3+4+3 = 10.

We have that m1 is at point P1(2,-6), m2 at point P2(-3,2) and m3 at point P3 (3,4), then

$M_x = \sum_{n=1}^k m_n\cdot y_n = 3\cdot(-6)+4\cdot(2)+3\cdot(4)=2$

$M_y = \sum_{n=1}^k m_n\cdot x_n = 3\cdot(2)+4\cdot(-3)+3\cdot(3)= 3$

Then, the center of Mass is at $(\frac{3}{10},\frac{2}{10})$

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3 years ago

Determine the functions value when x=-1

ladessa [460]

Answer:

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Step-by-step explanation:

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3 years ago

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evablogger [386]

Answer:

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3 years ago

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Does anyone know the answer to this? If so can u please help me.

AlexFokin [52]

Answer:

$m\angle M = 90\degree\\m\angle L = 24\degree$

Step-by-step explanation:

LM is tangent to the circle at point M and NM is radius.

$\therefore NM\perp LM.. (radius \perp tangent) \\\huge\orange {\boxed {m\angle M = 90\degree}} \\$

By interior angle sum postulate of a triangle, we have:

$m\angle L + m\angle M + m\angle N = 180\degree \\m\angle L + 90\degree + 66\degree = 180\degree \\m\angle L + 156\degree = 180\degree \\m\angle L = 180\degree - 156\degree \\\huge\red {\boxed {m\angle L = 24\degree}} \\$

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4 years ago