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exis [7]
2 years ago
8

Find the sum: (x^5 - 2x^4 + 3x^2 - 6) + (3x^4 + 4x^2 + x + 4). Enter your answer as a

Mathematics
1 answer:
stich3 [128]2 years ago
4 0

Answer:

The sum of the two equation is x^5 + x^4 + 7x^2 + x -2

Step-by-step explanation:

The given two equations are

(x^5 - 2x^4 + 3x^2 - 6)\\ (3x^4 + 4x^2 + x + 4)

Now rearranging the two equation in such a way that variables with similar with same power are grouped together -

x^5 - 2x^4 + 3x^4  + 3x^2 + 4x^2 + x- 6+ 4\\x^5 + x^4 (3-2) + x^2 (3+4) + x -6+4\\x^5 + x^4 + 7x^2 + x -2

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Answer:

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Step-by-step explanation:

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3 years ago
-14(3a+6)=12(6-4a)+12 and steps please
Sunny_sXe [5.5K]

Answer:

In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

Step-by-step explanation:

Given equation is -14(3a+6)=12(6-4a)+12

To simplify the given equation:

-14(3a+6)=12(6-4a)+12

Taking all terms to one side

-14(3a+6)-12(6-4a)-12=0

-[14(3a+6)+12(6-4a)+12]=0

Now dividing by negative sign on the above equation we get

14(3a+6)+12(6-4a)+12=0 (using distributive property)

42a+84+72-48a+12=0 ( adding the like terms )

-6a+168=0

-6a=-168

6a=168

a=\frac{168}{6}

Therefore a=28

Therefore in the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28

8 0
3 years ago
If 18 793is multiplied by 1000 then what is the product​
Yakvenalex [24]

Answer:

18793000

Step-by-step explanation:

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2 years ago
These are lines in a plane that are always the same distance apart and never intersect. What are they? *​
Pavlova-9 [17]

Answer:

Parallel lines

Step-by-step explanation:

Parallel lines never intersect and are always same distance apart.

Hope this helps, thank you :) !!

3 0
3 years ago
Read 2 more answers
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Answer:

-2

Step-by-step explanation:

Hope It Helps

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