DB/dt = k*B
dB/(kB) = dt
Integrating both sides:
1/k*ln|B| = t + C
B = C*e^(kt)
At time t = 0, B = 4000 and at time t = 3 (3 hours past 9 AM), B = 4500
4000 = C
4500 = 4000*e^(3k) => k = 1/3*ln(9/8)
At time t = 15 (Midnight), B = 4000*e^(1/3*ln(9/8)*15) = 4000*(9/8)^5 = 7208 bacteria
The common difference is 3
Answer:
71%
Step-by-step explanation:
Firstly, 200 - 58 = 142
Next, 142 / 200 = 0.71
0.71 x 100 = 71%
507 peaches in each box.
He gives away 5 peaches.
If he sells 7 boxes he has 1019 peaches left.
Hope this helps.
Answer:
(a) 3 added to twice the value of n
(b) 
Step-by-step explanation:
Given
Table #27
Solving (a): First, we express as an equation
The table illustrates a linear function; so, we calculate the slope (m) first

Where:


So:




The equation is then calculated using:




In words, the equation is: <em>3 added to twice the value of n</em>
Solving (b): As an equation.
This has been solved in (a) above:
