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3 years ago

6

The table shows information about some children.

1 answer:

Sindrei [870]3 years ago

3 0

Answer:

$P(Age\ 12) = \frac{2}{3}$

Step-by-step explanation:

Given

Age 11 Age 12 Total

Girls 3 5 8

Boys 1 3 4

Required

$P(Age\ 12)$

The number of aged 12 children is:

$Age\ 12 = 5 + 3$

$Age\ 12 = 8$

The total number of children is:

$Total=8+4$

$Total = 12$

So, we have:

$P(Age\ 12) = \frac{Age\ 12}{Total}$

$P(Age\ 12) = \frac{8}{12}$

Simplify

$P(Age\ 12) = \frac{2}{3}$

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storchak [24]

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Answer:

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Step-by-step explanation:

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How many terms does the polynomial have?

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Step-by-step explanation:

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3 years ago

If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are:

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$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0$

Maximum ( $\cos \theta = 1$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1$

With the help of a graphing tool we get the family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

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2 years ago

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ANEK [815]

Answer:

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Step-by-step explanation:

Hello!! I for got how to solve this but, I think it is:

68 x 0.60 = 40.8

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Troyanec [42]

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3 years ago