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Sunny_sXe [5.5K]
3 years ago
11

Is y= x + 3/5x. Or y=x(1+3/5) the correct answer

Mathematics
1 answer:
gregori [183]3 years ago
6 0

Answer:

I think y=x (1+3/5) is the right answer.

Step-by-step explanation:

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Factor 64 - P.<br> (8 - x(8 - x)<br> (8 + x (8 - x)<br> (X + 8)(x-8)
muminat

Question:

Factor 64-x^2

(8 - x)(8 - x)

(8 + x) (8 - x)

(X + 8)(x-8)

Answer:

Option B: (8+x)(8-x) is the factor

Explanation:

Given that the expression is 64-x^2

We need to find the factor of the given expression.

Let us rewrite the expression as 8^2-x^{2}

Since the expression is of the form a^2-b^2, let us use the identity a^2-b^2=(a+b)(a-b)

where a = 8 and b = x

Substituting the values in the identity, then the expression can be written as

8^2-x^{2}=(8+x)(8-x)

Thus, the factor of the expression is (8+x)(8-x)

Hence, Option B is the correct answer.

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3 years ago
What is the mean of variable a<br><br><br><br><br><br>piz help me i have one more question
timama [110]
I think the mean of variable a is 4
4 0
3 years ago
A biker travels 10 miles in two hours, what is his speed?
Alinara [238K]

Answer:

5 mph

Step-by-step explanation:

10/2 is 5 miles in one hour.

7 0
3 years ago
Read 2 more answers
Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)
borishaifa [10]

Answer:

Since,

\frac{d}{dx}x^n = nx^{n-1}

\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))

\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}

1) y = 8x e^x

Differentiating with respect to x,

\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)

2) y = 5x e^{x^4}

Differentiating w. r. t x,

\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)

3) y = x^8 + \frac{5}{x^4}

Differentiating w. r. t. x,

\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}

4) f(t) = te^{11}-6t^5

Differentiating w. r. t. t,

f'(t) = e^{11} - 30t^4

5) g(p) = p\ln(2p+3)

Differentiating w. r. t. p,

g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)

6) z = (te^{6t}+e^{5t})^7

Differentiating w. r. t. t,

\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})

7) w =\frac{2y + y^2}{7+y}

Differentiating w. r. t. y,

\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}

7 0
4 years ago
Factorize B (A)<br>IBG) - (7a-41² -214-72) 1483) 1716​
Firlakuza [10]
Your solution to your question would be 7a - 1967
5 0
3 years ago
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