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Rasek [7]
3 years ago
10

Please help me, Thanks.

Mathematics
1 answer:
Lady_Fox [76]3 years ago
3 0

Answer:

6.9

Step-by-step explanation:

6 \frac{4}{5}  = 6.8

6.9 > 6.8

6.9 < 7

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I need the answers to this question
pshichka [43]
I am sorry I am not in that level yet
4 0
3 years ago
Two lines, A and B, are represented by the following equations:
almond37 [142]

Answer:

D.

Step-by-step explanation:

The solution is where the lines intersect which is at the point (3,2).

So the answer is Option D.

The point (3,2) satisfies both equations.

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4 years ago
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Describe the graph of the equation y = 6x.
Illusion [34]

y = 6x

y = (8.9) (9.8)

y = 6x (8.9)

y = 8.9x

4 0
3 years ago
When using the inspection method, the number you would add to (and subtract from) the constant term of the numerator so the poly
krok68 [10]

Question:

Consider the expression \frac{x^2 + x -10}{x + 3}

When using the inspection method the number you would add to (and subtract from) the constant term of the numerator so the polynomial in the numerator will have (x + 3) as a factor is?

Answer:

The constant to add is 4

Step-by-step explanation:

Given

\frac{x^2 + x -10}{x + 3}

First, we need to get an expression that has x + 3 has its factor.

Represent this expression with: (x + 3)(x + k)

Expand

x^2 + 3x + kx + 3k

Group like terms

x^2 + (3 + k)x + 3k

Compare the above expression to: x^2 + x - 10

(3 + k)x = x

3k = -10

However, we only consider solving (3 + k)x = x for k

(3 + k)x = x

3 + k = 1

Subtract 3 from both sides

3 - 3 + k = 1 - 3

k = 1 - 3

k= -2

Substitute -2 for k in (x + 3)(x + k)

(x + 3)(x + k) = (x + 3)(x -2)

(x + 3)(x + k) = x^2 + 3x - 2x - 6

(x + 3)(x + k) = x^2 + x - 6

So, the expression that has a factor of x + 3 is x^2 + x - 6

To get the constant term to add/subtract, we have:

Constant = (x^2 + x - 6) - (x^2 + x - 10)

Open brackets

Constant = x^2 + x - 6 - x^2 - x + 10

Collect Like Terms

Constant = x^2 - x^2+ x   - x - 6+ 10

Constant =  - 6+ 10

Constant =  4

6 0
3 years ago
Write an expression for the net change in charge if two electrons are added to each of six atoms in a group. Also, write an expr
dusya [7]

Given:

Two electrons are added to each of six atoms in a group.

To find:

The expression for the net change in charge.

Solution:

Charge of atoms = Number protons - Number of electrons.

Let number of atoms be x.

6 atoms = 2 electrons added

1 atom = \dfrac{2}{6} electrons added

1 atom = \dfrac{1}{3} electrons added

x atoms = \dfrac{1}{3}x electrons added

Therefore, the net change in charge is represented by the expression -\dfrac{1}{3}x because we subtract number of electrons to find atom charge, where, x is the number of atoms.

6 atoms = 2 protons removed

1 atom = \dfrac{2}{6} protons removed

1 atom = \dfrac{1}{3} protons removed

x atoms = \dfrac{1}{3}x protons removed

Therefore, the net change in charge is represented by the expression -\dfrac{1}{3}x, where, x is the number of atoms.

6 0
3 years ago
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