To find the gradient you do change in y/change in x so...
-12 - 0
————- = -12/4 = -3
0 - - 4
Hope this helps! Any questions let me know :)
Answer:
2x^3 + 3x^2 -27x +40
Step-by-step explanation:
(x+5) (2x²-7x+8)
2x^3 + 3x^2 + 8x + 10x^2 - 35x + 40
2x^3 + 3x^2 - 27x + 40
Steps To Solve:
x² + 6 = 10
~Subtract 6 to both sides
x² + 6 - 6 = 10 - 6
~Simplify
x² = 4
~Take square root of 4
x² = ±√4
~Simplify
x = -2 or x = 2
Best of Luck!
Answer:
Sure
Step-by-step explanation:
f(x)=4x+2 g(x)=-2x+8 h(x)=(-1/4)x-5
1)t(x)=f(x)-3
t(x)=4x+2-3
t(x)=4x-1
2)p(x)=5+3(g(x))
p(x)=5+3(-2x+8)
p(x)=5-6x+24
p(x)=29-6x
3)w(x)=2f(x)+h(x)
w(x)=2(4x+2)+(-1/4)x-5
w(x)=8x+4-(1/4)x-5
w(x)=31/4(x)-1
4)z(x)=f(x)-h(x)-g(x)
z(x)=4x+2-(-1/4)x-5--2x+8
z(x)=4x+0.25x+2x+2+5-8
z(x)=6.25x-1
5)d(4)? d(x)=h(x)+g(x)
d(x)=((-1/4)x-5)+(-2x+8)
d(4)=((-1/4)(4)-5)+(-2(4)+8)
d(4)=(-2-5)+(-8+8)
d(4)=-7
6)r(-3)? r(x)=2g(x)+3f(x)
r(x)=2(-2x+8)+3(4x+2)
r(x)=-4x+16+12x+6
r(x)=-8x+22
r(-3)=8(-3)+22
r(-3)=-24+22
r(-3)=-2
7)l(8)? l(x)=f(x)-h(x)+h(x)
l(x)=4x+2
l(8)=4(8)+2
l(8)=34
8)c(-24)? c(x)=2h(x)-2g(x)+1/2f(x)
c(x)=2((-1/4)x-5)-2(-2x+8)+0.5(4x+2)
c(x)=0.5x-10+4x-8+2x+1
c(x)=6.5x-17
c(-24)=6.5(-24)-17
c(-24)=173
I do not know what you mean by the wording of some of these questions, so I will just give you the formula and tell you how to apply it. The formula of the Pythagorean Theorem is a^2 + b^2 = c^2. a and b are the two sides adjecent to the right angle (in the corner). c is the side opposite the right angle. So, to get c you would have to add sides a and b but with each of them to the second power. Then, you would find the square root of the sum (you can do this with a calculator). To find sides a or b, subtract a or b (whichever one available) to the second power from c to the second power. Then find the square root of the sum. That is all I know how to do, so combine this knowledge with yours to see if you can solve it. If you have any questions about what I already know, feel free to ask. You can also ask for an example. If you have a question about something that I have not explained, look it up on the internet, or hopefully you can find someone who can help you. I hope this helps.