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dexar [7]
3 years ago
6

Help me please :> I would really appreciate it.

Mathematics
2 answers:
REY [17]3 years ago
8 0
Yes
Yes
No

That’s your answer
rosijanka [135]3 years ago
4 0

Answer:

no

yes

no

Check to see if your equation has exponents. If it has exponents, it is nonlinear. If your equation has no exponents, it is linear.

Hope it helped!!!

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How many perpendicular lines must be drawn in a triangle to prove the Law of Sines?..is it 2, 1,0, or 3..Explain
Butoxors [25]

Answer:

We show 1 to distinguish a vertex, but with laws of supplementary the answer is 2.

Step-by-step explanation:

7 0
3 years ago
Do you have to have 10on a number line to show a decimal
mixas84 [53]
No. The line just has to go below ' 1 '.
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3 years ago
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What is the equation of the line that is parallel to the line 2x+3y=-8 and passes through the point (2,-2)?
Leya [2.2K]

Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is y=\frac{-2 x}{3}+\frac{-2}{3}

<h3><u>Solution:</u></h3>

Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)

Generic slope intercept form of a line is given by y = mx + c

where "m" = slope of the line and "c" is the y - intercept

Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

\begin{array}{l}{2 x+3 y=-8} \\\\ {=>y=\frac{-2 x-8}{3}} \\\\ {\Rightarrow y=-\frac{2}{3} x-\frac{8}{3}}\end{array}

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

\text {for line } 2 x+3 y=-8, \text { slope } m=-\frac{2}{3}

We know that slopes of parallel lines are always equal

So the slope of line passing through (2, -2) is also m=-\frac{2}{3}

Equation of line passing through (x_1 , y_1) and having slope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=2 \text { and } y_{1}=-2

Substituting the values in equation of line we get

(y-(-2))=-\frac{2}{3}(x-2)

\begin{array}{l}{\Rightarrow y+2=\frac{-2 x+4}{3}} \\\\ {=>3(y+2)=-2 x+4} \\\\ {=>3 y+6=-2 x+4} \\\\ {3 y=-2 x-2}\end{array}

y=\frac{-2 x}{3}+\frac{-2}{3}

Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as y=\frac{-2 x}{3}+\frac{-2}{3}

7 0
3 years ago
What is the slope of the line shown below?
melisa1 [442]

Answer:

C. 2

Step-by-step explanation:

Gradient = \frac{change in y}{change in x}

Gradient = \frac{6}{3}

Gradient = 2

7 0
2 years ago
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The polynomial below is a perfect square trinomial of the form A^2-2AB+B^2. 9x^2-18x+36
baherus [9]
No, It's not.

coefficients for perfect square would be:
3² - 2(3)(6) + 6² = 9 - 36 + 36

8 0
3 years ago
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