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Elis [28]
3 years ago
10

HELP DUE IN 20 minutes

Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0
Shortest to longest

C
B
A
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helpppp! The population of a town is 20,000 people in the year 2000. How many people with live in the town in 2016 if the popula
Brut [27]

Answer:

31877 people with live in the town in 2016 if the population increases at a rate of 6% every 2 years

Step-by-step explanation:

The formula used will be

A(t) = P(1+r)^t

A(t) = Future value

P = population

r = rate

t = time

P= 20,000

r =6% or 0.06

t = 16

Since population is increased every 2 years, so t = 16/2 = 8

Putting value:

A(16) = 20,000(1+0.06)^8

A(16)= 20,000(1.06)^8

A(16) = 31876.9 ≈ 31877

So, 31877 people with live in the town in 2016 if the population increases at a rate of 6% every 2 years

5 0
3 years ago
7y-4=17 what is the answer
yaroslaw [1]

Answer:

7y=21

y=21/7

y=3 answer

3 0
3 years ago
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Do 1-15 pls and who ever does it will get free v-bucks tonight
Sunny_sXe [5.5K]
These are the answers, if it is blurry I can retake the picture but I hope this helped.

6 0
3 years ago
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12. (24.4D) For what value of c will the graphs of
weqwewe [10]

Answer:

c=144

Step-by-step explanation:

we have

y=2x^2-36x+c ---> equation A

y=2(x-9)^2-18 ---> equation B

Convert the equation A into vertex form and then compare with equation B

we have

y=2x^2-36x+c

Factor 2 leading coefficient

y=2(x^2-18x)+c

Complete the square

y=2(x^2-18x+81)+c-162

Rewrite as perfect squares

y=2(x-9)^2+(c-162)

Compare with equation B

c-162=-18

solve for c

c=-18+162

c=144

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3 years ago
Which expression gives the measure of 2ACE in the diagram below*
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