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Wittaler [7]
3 years ago
12

Can’t figure this out!

Mathematics
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

what does it say because i cant see

St ep-by-step explanation:

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Make a box ­and ­whisker plot of the data.<br><br> 24, 18, 29, 21, 16, 23, 13, 11
Elanso [62]
To make a box and whisker plot you must first order the data:

11, 13, 16, 18, 21, 23, 24, 29

Then find the median:

19.5

Then split the data into two sections by the median:

11, 13, 16, 18 and 21, 23, 24, 29

Now find the medians of those sets

14.5 and 23.5

With this information we can conclude Option C is the correct plot

Hope this helps!
7 0
3 years ago
Read 2 more answers
An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
Add the following:
PIT_PIT [208]

Step-by-step explanation:

1) 7/23 + 11/23 + 9/23

7+11+9/23

27/23

= 1 4/23

2) 2 5/7 + 9 4/7

11 9/7

= 11.12

3) 9/20 + 3/5

9+12/20

21/20

= 1 1/20 or 1.05

8 0
3 years ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
poizon [28]

Answer: y=-3x+29

Step-by-step explanation:

First put in y-intercept form to find the slope

4x-12y=2\\-12y=-4x+2\\y=\frac{1}{3} x-\frac{1}{6}

Slope of the 1st equation is 1/3-  the slope of the line perpendicular is the opposite reciprocal, so in the case it is -3

Use the point and the new slope to write the new equation in point slope format

y-y_{1} =m(x-x_{1} )\\y-(-1)=-3(x-10)\\y+1=-3x+30\\y=-3x+29

8 0
3 years ago
How big is the home field advantage in the National Football League (NFL)? To investigate, we select a sample of 80 games from t
ElenaW [278]

Answer:

0.74 to 6.06

Step-by-step explanation:

The groups are independnet,

SE(xh bar-xa bar)=sqrt [sh^2/nh+sa^2/na]=sqrt [10.1^2/80+10.3^2/80]=1.61

At df=157, the t critical is 1.65

90%c.i=(xh bar-xa bar)+-tcritical SE(xh bar-xa bar)

=(25.2-21.8)+-1.65*1.61

=0.74 to 6.06

5 0
3 years ago
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