Let 
be the area of the sector in the larger circle (radius 12 cm) whose central angle is subtended by the labeled arc with measure 45 deg, and let 
be the area of the sector in the smaller circle (radius 8 cm) with the same central angle. The area you want is 
.
We have
So the area of the shaded region is 
.
It looks like the integral is
where <em>D</em> is the set
<em>D</em> = {(<em>x</em>, <em>y</em>) : 0 ≤ <em>x</em> ≤ 1 and <em>x</em> ² ≤ <em>y</em> ≤ √<em>x</em>}
So we have
Answer:
Co-ordinates of the focus is; (0, -4)
Step-by-step explanation:
We are given;
Vertex at origin; (0, 0)
Equation of parabola; y = x²/4p
4p = -16
Now,in parabola with vertex at origin, the coordinates of the focus is usually at (0, p)
Now, from 4p = -16 we can find p
p = -16/4
p = -4
Thus coordinates of the focus is; (0, -4)
He would have to multiply by 1.03
answer:
slope: -2/3
step-by-step explanation:
y=mx+b
m represents the slope, and b the y-intercept.
rearrange: 9x= -6y+18
---> -6y= -9x-18
divide all terms by -6.
-6y/-6= -9/-6x-18/-6
y= 3/2x+3 (slope/intercept form)
m= 3/2
---> 1/3/2= -2/3
