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Sedbober [7]
3 years ago
7

Find the first four terms of the sequence given by the following. an=43-6(n-1), n=1, 2, 3.

Mathematics
1 answer:
777dan777 [17]3 years ago
7 0

Step-by-step explanation:

Your answer is

43,37,31,25

Hope that this is helpful. Tap the crown button, Like & Follow me

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Round 913,610 to nearest ten
Harlamova29_29 [7]
913,610 it is the same number because 0 is less than 5 so you don't have to round the tens place up by one
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10. How can you identify a and b from a situation?
8_murik_8 [283]

Answer:

a would be slope and b would be y-intercept.

m and b are usually the ones a lot of people use. m is slope and b is y-intercept.

8 0
2 years ago
Adam sells medical magazines
velikii [3]

Let the Price of 1 magzine = x

       Margin on 1 Magzine = (10%)(x) rupees = 0.1 x    

       Margin on 42 Magzines = 42(0.1 x) = 4.2 x    

Also

Let the Price of 1 books = y

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Basic Pay of Adam = 200

Amount that Adam earned last week = 200 + 4.2 x  + 2.1 y

2.3

8 0
4 years ago
Determine the next step for solving the quadratic equation by completing the square.
nexus9112 [7]

\qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

the idea behind the completion of the square is simply using a perfect square trinomial,  hmmm usually we do that by using our very good friend Mr Zero, 0.

if we look at the 2nd step, we have a group as x² - x, hmmm so we need a third element, which will be squared.

keeping in mind that the middle term of the perfect square trinomial is simply the product of the roots of "a" and "b",  so in this case the middle term is "-x", and the 1st term is x², so we can say that

\stackrel{middle~term}{2(\sqrt{x^2})(\sqrt{b^2})~}~ = ~~\stackrel{middle~term}{-x}\implies 2xb~~ = ~~~~ = ~~-x \\\\\\ b=\cfrac{-x}{2x} \implies b=-\cfrac{1}{2}

so that means that our missing third term for a perfect square trinomial is simply 1/2, now we'll go to our good friend Mr Zero, if we add (1/2)², we have to also subtract (1/2)², because all we're really doing is borrowing from Zero, so we'll be including then +(1/2)² and -(1/2)², keeping in mind that 1/4 - 1/4 = 0, so let's do that.

-3~~ = ~~-2\left[ x^2-x+\left( \cfrac{1}{2} \right)^2 ~~ - ~~\left( \cfrac{1}{2} \right)^2\right]\implies -3=-2\left(x^2-x+\cfrac{1}{4}-\cfrac{1}{4} \right) \\\\\\ -3=-2\left(x^2-x+\cfrac{1}{4} \right)+(-2)-\cfrac{1}{4}\implies -3=-2\left(x^2-x+\cfrac{1}{4} \right)+\cfrac{1}{2} \\\\\\ -3-\cfrac{1}{2}=-2\left(x^2-x+\cfrac{1}{4} \right)\implies -\cfrac{7}{2}=-2\left(x-\cfrac{1}{2} \right)^2\implies \cfrac{7}{4}=\left(x-\cfrac{1}{2} \right)^2

~\dotfill\\\\ \pm\sqrt{\cfrac{7}{4}}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}+\cfrac{1}{2}=x \implies \cfrac{\pm\sqrt{7}+1}{2}=x

8 0
2 years ago
A zookeeper is monitoring the population of gazelles. The herd needs three times more males than females to thrive, and the zoo
avanturin [10]

Answer:

0 < x ≤ 12 and 0 < y ≤ 36

Step-by-step explanation:

Here,  x represents the number of female gazelles and y represents  the number of male gazelles.

The zoo only has room for 12 female gazelles.

∵ The number of rooms must be more than or equal to the total female gazelles ,

12 ≥ x

Also, number of animals can not be negative,

And, it must be greater than 0.

⇒ 0 < x ≤ 12,

⇒ 3(0) < 3x ≤ 3(12)

⇒ 0 < 3x ≤ 36

∵ Number of males gazelles = 3 × number of female gazelles

⇒ y = 3x

⇒ 0 < y ≤ 36

Hence, the constraints to represent a thriving population of gazelles at the zoo are,

0 < x ≤ 12,

0 < y ≤ 36

7 0
3 years ago
Read 2 more answers
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