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liubo4ka [24]
2 years ago
15

If Brian biked at an average speed of 12.2 miles per hour for 1.45 hours, you can find the total distance by multiplying

Mathematics
2 answers:
gavmur [86]2 years ago
7 0

Answer:

First, multiply the numbers. Then count the number of decimal places in each factor. Place the decimal in the product so the product has the same number of decimal places as both factors combined.

Step-by-step explanation:

Did it on Edg.2020

ololo11 [35]2 years ago
6 0

Answer: First, multiply 12.2 times 1.45. Next, you start by multiplying the ones, then the tens, and then the hundreds. Next, you add the partial products. then you count the number of digits to the right of the original problem. Then you move the decimal the same number of digits to the left in the product.

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What’s the relationship between these two angles?
Dovator [93]

Answer:

Co- interior angles

Step-by-step explanation:

Together they add up to 180°

So angle 5x= 115°

5 0
2 years ago
What is the quotient of 2/5 divided by 3/7<br><br>A. 15/14<br>B. 14/15<br>C. 35/6<br>D. 6/36​
STALIN [3.7K]

Answer:

= { \tt{ \frac{2}{5}  \div  \frac{3}{7} }} \\  \\  = { \tt{ \frac{2}{5} \times  \frac{7}{3}  }} \\  \\  = { \underline{ \tt{ \:  \:  \frac{14}{15}  \:  \: }}}

<u>Answer</u><u>:</u><u> </u><u>B</u>

8 0
2 years ago
Read 2 more answers
The sum of the first n terms of an arithmetic sequence is n/2(4n + 20).
lesantik [10]

Answer:

(a).

S_{n} =  \frac{n}{2} (4n + 20) \\  \\S _{n - 1} =  \frac{(n - 1)}{2} (4n - 4 + 20) \\  \\ S _{n - 1} =  \frac{(n - 1)}{2} (4n + 16) \\  \\S _{n - 1} = \frac{(n - 1)(4n + 16)}{2}  \\   \\  { \boxed{S _{n - 1} =  {2 {n}^{2} + 6n - 8}}} \\

(b).

from general equation:

S _{n - 1} =  \frac{(n - 1)}{2} (4n + 16)

first term is 4n

common difference:

16 =  \{(n - 1) - 1 \}d \\ 16 = (n - 2)d \\ d =  \frac{16}{n - 2}

8 0
3 years ago
Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
3 years ago
This graph shows the tempature in Diego’s between moon and midnight one day. Choose ALL of the statements that are true.
tia_tia [17]
All of them are right
6 0
3 years ago
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