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lesya692 [45]
3 years ago
13

A local parking garage charges $5 for the first hour and $1.25 for each additional hour. Write an equation in function notation

form. Tell me how much it would cost if you left your car for a total of 6 hours.
Mathematics
1 answer:
JulijaS [17]3 years ago
4 0
Y=5+1.25x x=6 Meaning at 6 hours it would cost $12.50
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Rhonda hiked 260.4 feet and hiked 3 more hours and I got that by adding 1.5+1.5=3 but what do I do
Hunter-Best [27]
1.5 + 1.5 + 2 = 5 hours 
All you must do is: 260.4 / 5 = ? 
6 0
3 years ago
Integrate x<br><img src="https://tex.z-dn.net/?f=x4" id="TexFormula1" title="x4" alt="x4" align="absmiddle" class="latex-formula
Dmitrij [34]

Answer:

The result of the integration is \frac{x^5}{5}

Step-by-step explanation:

Integration of a power of x:

The integration of a power of x is:

\int x^{n} dx = \frac{x^{n+1}}{n+1}

In this question:

n = 4. So

\int x^{4} dx = \frac{x^{4+1}}{4+1} = \frac{x^5}{5}

The result of the integration is \frac{x^5}{5}

4 0
3 years ago
I new help with number 1 and number 2
Natalka [10]
I hope this helps you

4 0
4 years ago
Graph the hyperbola using the transverse axis, vertices, and co-vertices:
Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

#SPJ1

4 0
2 years ago
Which expression is equivalent to 5y^3/(5y)^-2​
Serggg [28]

Answer:

5^3  y^5

125 y^5

Step-by-step explanation:

5y^3/(5y)^-2​

Distribute the exponent in the denominator

5y^3/(5 ^-2 y^-2)

A negative exponent in the denominator brings it to the numerator

5y^3 5 ^2 y^2​​

Combine like terms

5 * 5^2  * y^3 5^2

We know that a^b * a^c = a^(b+c)

5^(1+2) * y^( 3+2)

5^3  y^5

125 y^5

6 0
3 years ago
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