At the peak of a roller coaster ride, the rider's watch flew off his wrist. The height h in feet of the watch, t seconds after h

Question

Maru [420]

3 years ago

9

At the peak of a roller coaster ride, the rider's watch flew off his wrist. The height h in feet of the watch, t seconds after h

e lost it, is given by y= -16x^2 + 32x + 48. How many seconds did it hit the ground?

Mathematics

2 answers:

enot [183] · Answer 1 · 2022-03-11T08:13:37+03:00

enot [183]3 years ago

7 0

Answer:

Step-by-step explanation:

You can't do anything but substitute for h and t in this question.

t = x

y = h

h = -16t^2 + 32t + 48

This is not a calculus course I don't think, so this is your answer.

defon · Answer 2 · 2022-03-11T06:58:22+03:00

defon3 years ago

6 0

Answer:

$3 \: s$

Step-by-step explanation:

$y = - 16 {x}^{2} + 32x + 48 \\ 0 = \frac{ - 16 {x}^{2} + 32x + 48 }{ - 16} \\0 = {x}^{2} - 2x - 3 \\ 0= {x}^{2} - 3x + x - 3 \\ 0= x(x - 3) + 1(x - 3) \\0 = (x + 1)(x - 3) \\ \\ x + 1 = 0 \\ x = - 1 \\ x - 3 = 0 \\ x = 3$

Hope this helps you.

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