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Maru [420]
3 years ago
9

At the peak of a roller coaster ride, the rider's watch flew off his wrist. The height h in feet of the watch, t seconds after h

e lost it, is given by y= -16x^2 + 32x + 48. How many seconds did it hit the ground?​
Mathematics
2 answers:
enot [183]3 years ago
7 0

Answer:

Step-by-step explanation:

You can't do anything but substitute for h and t in this question.

t = x

y = h

h = -16t^2 + 32t + 48

This is not a calculus course I don't think, so this is your answer.

defon3 years ago
6 0

Answer:

3 \: s

Step-by-step explanation:

y =  - 16 {x}^{2}  + 32x + 48 \\ 0 =  \frac{ - 16 {x}^{2} + 32x + 48 }{ - 16}  \\0  =  {x}^{2}   - 2x - 3 \\   0= {x}^{2}  - 3x + x - 3 \\  0= x(x - 3)  + 1(x - 3) \\0  = (x + 1)(x - 3) \\  \\ x + 1 = 0  \\ x =  - 1 \\ x - 3 = 0 \\ x = 3

Hope this helps you.

<em>Can</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>brainliest</em><em> </em><em>please</em><em>?</em>

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4 0
3 years ago
What is the<br> the distance between a point at (-3,4) and a point at (2,-5)
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<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

What is the distance between a point at (-3,4) and a point at (2,-5) ?

<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

Let the two points be A and B .

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<h3>The distance between a point at (-3,4) and a point at (2,-5) is <u>1</u><u>0</u><u>.</u><u>3</u> . [Answer]</h3>
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