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Viefleur [7K]
2 years ago
12

Select the correct answer from the drop-down menu. Consider this system of linear equations: y − x = -13 -4x + 3y = -51 The solu

tion of the system of equations is .
Mathematics
1 answer:
Nookie1986 [14]2 years ago
5 0

Answer:

b

Step-by-step explanation:

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If a = 2 and b = -3, find the value of a3 - b2. <br> A.-31<br> B.-23<br> C.-1<br> D.15
valentinak56 [21]

Hello!

So let's first start out by solving the left side of the equation:

2 to the third power is 8

The right side now: -3 to the second power is -9

In total: 8- (-9)

So your answer is C) -1

I hope it helps!

3 0
3 years ago
Read 2 more answers
The equation x + y = z relates the whole numbers x, y, and z. How does z compare to x?
creativ13 [48]

Answer:

C. x is y less than z

Step-by-step explanation:

x+y=z

by using transposition

x = z-y

whatever x is, it is equal to the value of y taken from z

8 0
2 years ago
License plate numbers come in a variety of styles. (Ignore the fact that some choices of letters could not be used because they
avanturin [10]
Five digit is the answer
3 0
3 years ago
Five guys walk into a bar, how many ways can they sit so as to be arranged from oldest to youngest?
Ipatiy [6.2K]

There are 24 ways in which 5 guys can sit if arranged from oldest to youngest.

We have,

Five guys.

Now,

We know that,

Total number of ways to arranged around a table (n) = (n-1)!

So,

For n = 5,

I.e.

(n - 1)! = (5 - 1)! = 4!

So,

Total number of ways to arranged Five guys rom oldest to youngest (n) = (n-1)!

i.e.

= (5 - 1)! = 4!

We get,

= 4 × 3 × 2 × 1

i.e.

Total number of ways to arranged Five guys rom oldest to youngest (n) = 24.

Hence we can say that there are 24 ways in which 5 guys can sit if arranged from oldest to youngest.

Learn more about arrangement here

brainly.com/question/15032503

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8 0
2 years ago
Factor 1.21a^6+22a^3+100
Monica [59]

Answer:

\frac{1}{100} (11 {a}^{3} + 100)(11 {a}^{3} + 100)

Step-by-step explanation:

1.21 {a}^{6}  +  22 {a}^{3}  + 100 \\  = 1.21 {a}^{6}  +  11 {a}^{3}  +  11 {a}^{3}+ 100 \\  = 11 {a}^{3} (0.11 {a}^{3}  + 1) + 100(0.11 {a}^{3}  + 1) \\  = (0.11 {a}^{3}  + 1) (11 {a}^{3} + 100) \\  = ( \frac{11}{100}  {a}^{3}  + 1) (11 {a}^{3} + 100) \\ =   ( \frac{11{a}^{3}  + 100}{100}  ) (11 {a}^{3} + 100) \\  =  \frac{1}{100} (11 {a}^{3} + 100)(11 {a}^{3} + 100) \\ are \: the \: required \: factors.

4 0
3 years ago
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